multiline text values #255

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1. nlohmann commented on May 29, 2016

   

   nlohmann

   on May 29, 2016

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   Newline characters must be escaped, see RFC 7159, Section 7:

   All Unicode characters may be placed within the quotation marks, except for the characters that must be escaped: quotation mark, reverse solidus, and the control characters (U+0000 through U+001F).

   As \n is U+000A, it must be escaped. In your example, std::string s = "{\"text\":\"line 1\\nline 2\"}"; would be correct.
2. nlohmann

   closed this as completedon May 29, 2016
3. nlohmann

   added

   solution: invalidthe issue is not related to the librarythe issue is not related to the library

   on May 29, 2016
4. nlohmann commented on May 29, 2016

   

   nlohmann

   on May 29, 2016

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   (Side remark: Python fails to parse the string:

   Python 2.7.11 (default, Mar  6 2016, 18:11:07) 
   [GCC 4.2.1 Compatible Apple LLVM 7.3.0 (clang-703.0.21)] on darwin
   Type "help", "copyright", "credits" or "license" for more information.
   >>> s = "{\"text\":\"line 1\nline 2\"}"
   >>> s
   '{"text":"line 1\nline 2"}'
   >>> print s
   {"text":"line 1
   line 2"}
   >>> import json
   >>> json.loads(s)
   Traceback (most recent call last):
     File "<stdin>", line 1, in <module>
     File "/usr/local/homebrew/Cellar/python/2.7.11/Frameworks/Python.framework/Versions/2.7/lib/python2.7/json/__init__.py", line 339, in loads
       return _default_decoder.decode(s)
     File "/usr/local/homebrew/Cellar/python/2.7.11/Frameworks/Python.framework/Versions/2.7/lib/python2.7/json/decoder.py", line 364, in decode
       obj, end = self.raw_decode(s, idx=_w(s, 0).end())
     File "/usr/local/homebrew/Cellar/python/2.7.11/Frameworks/Python.framework/Versions/2.7/lib/python2.7/json/decoder.py", line 380, in raw_decode
       obj, end = self.scan_once(s, idx)
   ValueError: Invalid control character at: line 1 column 16 (char 15)
   
5. ins2718 commented on May 29, 2016

   

   ins2718

   on May 29, 2016

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   Thank you! Standard php-function "json_encode" not escaping new lines, so I thought it was the correct json-object. In python 3.5.1 is no exception.
6. nlohmann commented on May 29, 2016

   

   nlohmann

   on May 29, 2016

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   For Python 3.5.1, I get the same error:

   Python 3.5.1 (default, Dec  8 2015, 17:46:37) 
   [GCC 4.2.1 Compatible Apple LLVM 7.0.0 (clang-700.1.76)] on darwin
   Type "help", "copyright", "credits" or "license" for more information.
   >>> s = "{\"text\":\"line 1\nline 2\"}"
   >>> s
   '{"text":"line 1\nline 2"}'
   >>> print(s)
   {"text":"line 1
   line 2"}
   >>> import json
   >>> json.loads(s)
   Traceback (most recent call last):
     File "<stdin>", line 1, in <module>
     File "/usr/local/homebrew/Cellar/python3/3.5.1/Frameworks/Python.framework/Versions/3.5/lib/python3.5/json/__init__.py", line 319, in loads
       return _default_decoder.decode(s)
     File "/usr/local/homebrew/Cellar/python3/3.5.1/Frameworks/Python.framework/Versions/3.5/lib/python3.5/json/decoder.py", line 339, in decode
       obj, end = self.raw_decode(s, idx=_w(s, 0).end())
     File "/usr/local/homebrew/Cellar/python3/3.5.1/Frameworks/Python.framework/Versions/3.5/lib/python3.5/json/decoder.py", line 355, in raw_decode
       obj, end = self.scan_once(s, idx)
   json.decoder.JSONDecodeError: Invalid control character at: line 1 column 16 (char 15)
   

   But you are right for PHP's json_encode - strange that this function is not compliant to the JSON spec.