UnmarshalManyPayload with Links  #68

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1. ChrisCooney commented on Jan 26, 2017

   

   ChrisCooney

   on Jan 26, 2017

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   It's insane how this can be considered useable without the ability of deserialising a list of objects.

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2. aren55555 commented on Jan 27, 2017

   

   aren55555

   on Jan 27, 2017

   Contributor

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   @edisonspencer there is currently no one liner way to unmarshal a payload of the form:

   "data": [...], 
   "links": {...}
   

   However you can do something like:

   payload := new(ManyPayload)
   if err = json.NewDecoder(in).Decode(payload); err != nil {
   	t.Fatal(err)
   }

   And payload.Links should contain the Links Object at the "links" top level member. See this test for a more complete example: https://github.com/google/jsonapi/blob/master/request_test.go#L553
3. aren55555

   closed this as completedon Jan 27, 2017
4. rberlind commented on Nov 9, 2020

   

   rberlind

   on Nov 9, 2020

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   I believe the link in #68 (comment) should be https://github.com/google/jsonapi/blob/master/request_test.go#L694
5. rberlind commented on Nov 9, 2020

   

   rberlind

   on Nov 9, 2020

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   Also, it would be more helpful to have a working example that demarshalled a structure that used jsonapi structure tags.

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