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There are no option to no transform async/await #8838
Description
TypeScript Version:
- Version 1.9.0-dev.20160525-1.0
Code
// A self-contained demonstration of the problem follows...
async function getBar(params: number) {
return 1;
}transform into with --target ES6
Expected behavior:
- Don't transform async/await with polyfill codes.
- I would not like to transform async/awai in typescript phase, use babel or something to transform them, or use browser's natively support.
- In this case, I'd like to use TypeScript compiler as a very nice type checker and down transform to ECMA262's latest standard syntax.
Actual behavior:
var __awaiter = (this && this.__awaiter) || function (thisArg, _arguments, P, generator) {
return new (P || (P = Promise))(function (resolve, reject) {
function fulfilled(value) { try { step(generator.next(value)); } catch (e) { reject(e); } }
function rejected(value) { try { step(generator.throw(value)); } catch (e) { reject(e); } }
function step(result) { result.done ? resolve(result.value) : new P(function (resolve) { resolve(result.value); }).then(fulfilled, rejected); }
step((generator = generator.apply(thisArg, _arguments)).next());
});
};
function getBar(params) {
return __awaiter(this, void 0, void 0, function* () {
return 1;
});
}
Activity
mhegazy commentedon May 26, 2016
I believe you asking for
--t ESNexttarget. see #5361 (comment)this is tracked bu #5361
tetsuharuohzeki commentedon May 30, 2016
Ah, okay. Thank you.